In the given reaction C_6H_5-C(=O)-CH_3 xrigh | vedclass

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(A) Acetophenone reacts with hydroxylamine $(NH_2OH)$ in an acidic medium to form acetophenone oxime $(X)$. The reduction of this oxime with sodium an

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$C_6H_5-CH(NH_2)-CH_3$

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(A) Acetophenone reacts with hydroxylamine $(NH_2OH)$ in an acidic medium to form acetophenone oxime $(X)$. The reduction of this oxime with sodium and ethanol $(Na/C_2H_5OH)$ yields $1$-phenylethanamine $(Y)$. Reaction: $C_6H_5-C(=O)-CH_3 + NH_2OH \xrightarrow{H^{+}} C_6H_5-C(=NOH)-CH_3 (X) + H_2O$ $C_6H_5-C(=NOH)-CH_3 \xrightarrow{Na/C_2H_5OH} C_6H_5-CH(NH_2)-CH_3 (Y)$

In the given reaction $C_6H_5-C(=O)-CH_3$ $\xrightarrow{NH_2OH/H^{+}} X$ $\xrightarrow{Na/C_2H_5OH} Y$. $Y$ will be:

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